1st roll: Round 10: 
10
2nd roll: Round 10: Dare! 4, 5
Final score => 10 + 4 = 14 - 5 = 9
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welp
obviously had to wear flashy bottoms like that cat from animal crossing said
1 = 5
2 = 8, 10
FINAL = 5 - 2 = 3
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Okay you guys. Do you want to take a chance and do the House roll of 3d6?
If you get the same number: 1, 1, 1 etc - it’s a win, even if you’d don’t beat my roll when I close this round.
This is an offer to @asassinoBG, @joxter, @ljrounds and @anyamtikja
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8 4 7 final score 5
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the probability of that is extremely low
but it’s not like i have any other winning options, so if others are ok, i’m ok
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Is there a fail state?
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Nope. But, let’s make it a little easier. 2 of the same, instead of all 3. ^^
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So this would only enhance our chance to win?
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It’s an alternate chance, just in chance I roll high again. I’ve only roll the lowest - 3 - once in this whole game so far.
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So I don’t see why we all wouldn’t choose to also do this. But, how is it taking a chance? Is our previously rolled total for this round then not processed?
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It is. If I roll low, you guys are probably fine. If I roll high, then it’d suck to have a whole round of Tricks.
If I wanted to make it super easy, since the rolls aren’t high this round. I’d say roll 5d6 and get 2 of the same numbers out of the 5. That would be very likely, I’d think. 
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Since I still don’t understand, I’ll choose to continue on as before.
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Hi! To find out what I can do, say @discobot display help.
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